D0 central magnetic field

D. Adams
17may01 1120


The magnetic field for the D0 central tracker is provided by a solenoid with a nominal field of 2.0 T.

If we assume the field is constant, then the following holds for tracks that cross the beamline (i.e. those with zero impact parameter):

phi - phi0 = alpha
           = asin(K q/pT r)
           = asin(pTmin/pT)

where K = 0.003 GeV/c/cm

phi0 = phi direction at the beamline
phi = angular position at radius r
alpha = difference between the angular direction and position at radius r
pTmin = minimum |pT| which reaches radius r
If we take the outer radius of the tracker to be 50 cm, then the minimum pT which can reach this radius is
  pTmin = 150 MeV/c
Lower transverse momenta will curl up inside this radius.

Here are some values for alpha at r = 50 cm for charge +1e:

  pT      alpha
(GeV/c)   (deg)
-------   -----
   0.2    48.6
   0.3    30.0
   0.5    17.5
   1.0     8.6
   5.0     1.72
  10.0     0.86


dladams@fnal.gov